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3x^2=2x*10
We move all terms to the left:
3x^2-(2x*10)=0
We add all the numbers together, and all the variables
3x^2-(+2x*10)=0
We get rid of parentheses
3x^2-2x*10=0
Wy multiply elements
3x^2-20x=0
a = 3; b = -20; c = 0;
Δ = b2-4ac
Δ = -202-4·3·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-20}{2*3}=\frac{0}{6} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+20}{2*3}=\frac{40}{6} =6+2/3 $
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